1. If a discount of 25% off the retail price of a desk saves Mark $45, how much did he pay for the desk?
2. C: The following equation may be used to find the value of the car: 1,100 = 0.089x. Solving for x gives x ≈ 12,359.55. Thus, the value of the car is $12,359.55.
3. A: The formula, I = Prt, represents the amount of interest earned, for a particular principal, interest rate, and amount of time. Substituting 210 for I, 3000 for P and 0.07 for r gives: 210 = 3000(0.07)t. Solving for t gives t = 1. Thus, he will earn $210 in interest, after 1 year.
4. B: The percent increase may be modeled by the expression, (14,000-12,000)/12,000, which equals 16.7%.
5. E: The equation, 0.35x = 70, may be used to solve the problem. Dividing both sides of the equation by 0.35 gives x = 200.
6. B: The problem may be modeled as x = 0.05(2000). Thus, 100 is 5% of 2000.
7. C: The problem may be modeled as 90x = 27. Dividing both sides of the equation by 90 gives x = 0.3 or 30%.
8. D: The percent increase may be modeled by the expression, 0.75/15.50, which is approximately 0.048, or 4.8%.
9. A: The first part of the problem may be modeled with the equation, 45 = 1.2x. Solving for x gives x = 37.5. 80% of 37.5 may be written as 0.80(37.5), which equals 30.
10. C: The formula, I = Prt, represents the amount of interest earned, for a particular principal, interest rate, and amount of time. Substituting 600 for I, 2500 for P and 0.06 for r gives: 600 = 2500(0.06)t. Solving for t gives t = 4. Thus, she will have to wait 4 years to earn $600 in interest.
11. C: The second part of the problem may be modeled with the equation, 12 = 0.15x. Solving for x gives x = 80. Thus, the number is 80. 35% of 80 may be written as 0.35(80), which equals 28.
12. C: The sale price of the computer is 80% of the regular price. Thus, the following equation may be used to solve the problem: 1600 = 0.80x. Solving for x gives x = 2000. Thus, the regular price of the computer is $2000.
13. B: The following equation may be used to solve the problem: 0.25=(39,000-x)/x. Multiplying both sides of the equation by x gives 0.25x = 39,000 - x. Adding x to both sides of the equation gives 1.25x = 39,000, where x = 31,200. Thus, the cost of the SUV to the dealer was $31,200.
14. E: The problem may be modeled by the expression, 49,000 - (0.20(49,000)), which equals 39,200. Thus, he had to sell the car for $39,200.
15. B: The attendance of employees and spouses may be modeled as 1/2+1/3, or 5/6. Thus, 1/6 of those, in attendance, who are not employees or spouses, is approximately 16.7%.
16. B: The first part of the problem may be modeled with the equation, 6 = 0.24x. Solving for x gives x = 25. Thus, the number is 25. 40% of this number may be written as 0.40(25), which equals 10.
17. A: The problem may be modeled as 0.25(400), which equals 100.
18. B: The problem may be modeled as 0.22(900), which equals 198.
19. D: The percentage may be obtained by multiplying 0.45 by 100. Doing so gives 45%.
20. C: The percentage may be obtained by multiplying 1.25 by 100. Doing so gives 125%.
- $135
- $160
- $180
- $210
- $215
- $9.765.45
- $10,876.90
- $12,359.55
- $14,345.48
- $15,745.45
- 1 year
- 2 years
- 3 years
- 4 years
- 5 years
- 15%
- 16.7%
- 17.2%
- 85%
- 117%
- 100
- 110
- 150
- 175
- 200
- 50
- 100
- 150
- 200
- 250
- 15%
- 20%
- 30%
- 33%
- 41%
- 2.7%
- 3.3%
- 133%
- 4.8%
- 105%
- 30
- 32
- 36
- 38
- 41
- 2 years
- 3 years
- 4 years
- 5 years
- 6 years
- 5
- 12
- 28
- 33
- 62
- $1800
- $1900
- $2000
- $2100
- $2200
- $29,250
- $31,200
- $32,500
- $33,800
- $33,999
- $24,200
- $28,900
- $35,600
- $37,300
- $39,200
- 10.5%
- 16.7%
- 25%
- 32.3%
- 38%
- 8
- 10
- 15
- 20
- 25
- 100
- 200
- 800
- 10,000
- 12,000
- 90
- 198
- 250
- 325
- 375
- 0.045%
- 0.45%
- 4.5%
- 45%
- 0.0045%
- 0.125%
- 12.5%
- 125%
- 1250%
- 1250.5%
Answers & Explanations
1. A: The original price of the desk may be found by solving the equation, 0.25x = 45. Thus, x = 180. However, this is the original price of the desk. Since he saves $45, he pays $45 less, or $135.2. C: The following equation may be used to find the value of the car: 1,100 = 0.089x. Solving for x gives x ≈ 12,359.55. Thus, the value of the car is $12,359.55.
3. A: The formula, I = Prt, represents the amount of interest earned, for a particular principal, interest rate, and amount of time. Substituting 210 for I, 3000 for P and 0.07 for r gives: 210 = 3000(0.07)t. Solving for t gives t = 1. Thus, he will earn $210 in interest, after 1 year.
4. B: The percent increase may be modeled by the expression, (14,000-12,000)/12,000, which equals 16.7%.
5. E: The equation, 0.35x = 70, may be used to solve the problem. Dividing both sides of the equation by 0.35 gives x = 200.
6. B: The problem may be modeled as x = 0.05(2000). Thus, 100 is 5% of 2000.
7. C: The problem may be modeled as 90x = 27. Dividing both sides of the equation by 90 gives x = 0.3 or 30%.
8. D: The percent increase may be modeled by the expression, 0.75/15.50, which is approximately 0.048, or 4.8%.
9. A: The first part of the problem may be modeled with the equation, 45 = 1.2x. Solving for x gives x = 37.5. 80% of 37.5 may be written as 0.80(37.5), which equals 30.
10. C: The formula, I = Prt, represents the amount of interest earned, for a particular principal, interest rate, and amount of time. Substituting 600 for I, 2500 for P and 0.06 for r gives: 600 = 2500(0.06)t. Solving for t gives t = 4. Thus, she will have to wait 4 years to earn $600 in interest.
11. C: The second part of the problem may be modeled with the equation, 12 = 0.15x. Solving for x gives x = 80. Thus, the number is 80. 35% of 80 may be written as 0.35(80), which equals 28.
12. C: The sale price of the computer is 80% of the regular price. Thus, the following equation may be used to solve the problem: 1600 = 0.80x. Solving for x gives x = 2000. Thus, the regular price of the computer is $2000.
13. B: The following equation may be used to solve the problem: 0.25=(39,000-x)/x. Multiplying both sides of the equation by x gives 0.25x = 39,000 - x. Adding x to both sides of the equation gives 1.25x = 39,000, where x = 31,200. Thus, the cost of the SUV to the dealer was $31,200.
14. E: The problem may be modeled by the expression, 49,000 - (0.20(49,000)), which equals 39,200. Thus, he had to sell the car for $39,200.
15. B: The attendance of employees and spouses may be modeled as 1/2+1/3, or 5/6. Thus, 1/6 of those, in attendance, who are not employees or spouses, is approximately 16.7%.
16. B: The first part of the problem may be modeled with the equation, 6 = 0.24x. Solving for x gives x = 25. Thus, the number is 25. 40% of this number may be written as 0.40(25), which equals 10.
17. A: The problem may be modeled as 0.25(400), which equals 100.
18. B: The problem may be modeled as 0.22(900), which equals 198.
19. D: The percentage may be obtained by multiplying 0.45 by 100. Doing so gives 45%.
20. C: The percentage may be obtained by multiplying 1.25 by 100. Doing so gives 125%.
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